A uniform cylindrical puck of radius r and mass M is attached to the end of a cord that passes through a
hole in a fixed horizontal frictionless table. The center of the puck moves in a circle of
radius R with angular speed ω
8. The magnitude of the angular momentum of the puck about the hole is
So first I just calculate the Inertial moment of the pluck around the center of the table ,
I= Icylinder + M.R^2 = M(r^2/2 + R^2)
I would expect the answer: L to be simply that I times ω
but the correct answer is this WEIRD thing:
|L|= M (r^2/2 + R^2)^1/2 ω^2
I don't get it , where does that rootsquare term comes from and also why the ω^2????
Please help me out folks, I don't know what the heck am I doing wrong
