Hello everyone!
I hope you are all doing well! This is Mohamed Abdelhafez, a physics grad student @ the University of Chicago. As ETS recently released a new physics GRE test (GR1777) https://www.ets.org/s/gre/pdf/practice_book_physics.pdf, I have written down full solutions for it as part of a course I was teaching and you can find them here : http://home.uchicago.edu/~abdelhafez/pgre.php
I decided to share them as a tribute to this site and fellow sites that helped me a lot in my applications!
Please let me know if you have any comments/corrections, and best of luck to all of you who are starting this long journey of applying to physics PhD! Also, feel free to send me questions you have regarding grad life etc.
Mohamed
Physics GRE 1777 Solutions

 Posts: 1
 Joined: Thu Dec 08, 2016 8:36 am
Re: Physics GRE 1777 Solutions
Thanks for your great effort

 Posts: 2
 Joined: Tue Aug 08, 2017 9:33 pm
Re: Physics GRE 1777 Solutions
Dear all,
As some typos were pointed out, I updated the file today with the most recent version, so please download it again!
As some typos were pointed out, I updated the file today with the most recent version, so please download it again!
Re: Physics GRE 1777 Solutions
I saw question 100 on the PGRE I took in April 2016. Such a fun question to finish the exam with

 Posts: 5
 Joined: Wed Jul 18, 2018 12:09 am
Re: Physics GRE 1777 Solutions
Thanks for solutions. I am assuming this gr1777 exam is very representative of the actual exam
Re: Physics GRE 1777 Solutions
Can someone confirm the answer to question 100?
Re: Physics GRE 1777 Solutions
I think the rms deviation of Prob.41 should be coming from
the binomial error, which is sqrt(N*p*(1p)) = sqrt(100*0.1*0.9) = sqrt(9) = 3 rather
than sqrt(10), since this is a detectornot problem and should follow binomial
distribution rather than Poisson. Thanks!
the binomial error, which is sqrt(N*p*(1p)) = sqrt(100*0.1*0.9) = sqrt(9) = 3 rather
than sqrt(10), since this is a detectornot problem and should follow binomial
distribution rather than Poisson. Thanks!